Practica 3

porblema 1:

/* practica 3 problema 1
ezequiel*/
#include <conio.h>
#include <iostream.h>
#include <math.h>
int main ()
{
float X=1.672,Y=14.65,Z=1.845,W=2.45;
cout<<"\tEx npresion original\tExpresion con valores\t\tResultado\n"<<endl;
cout<<"\t2*Y*e^(W-Z) \t= \t"<<"2*"<<Y<<"*e^"<<"("<<W<<"-"<<Z<<")"<<" =\t"<<2*Y*exp(W-Z)<<endl;
cout<<"\tXsqrt(Y)+(X^3)\t= \t"<<"("<<X<<")"<<"sqrt"<<Y<<"+"<<X<<"^3"<<"=\t"<<X*sqrt(Y)+pow(X,2)<<endl;
cout<<"\t32.0Z/sqrt1.33(X)= \t"<<"32.0("<<Z<<")/sqrt1.33("<<X<<")"<<"= \t"<<32.0*Z/sqrt(1.33)*X<<endl;
cout<<"\t100.0/Y(e^2.66)+Z = \t"<<"100.0/"<<Y<<"e^(2.66)+"<<Z<<"= \t"<<100.0/Y*exp(2.66)+Z<<endl;
cout<<"\t8.86(e^2W)+4X = \t"<<"8.86(e^2"<<W<<")+4("<<X<<")=    \t"<<8.86*exp(2*W)+4*W<<endl;
getch ();
return(0);
}

problema 2:

/*practica 3 porblema 2
ezequiel */
#include <iostream h>
#include <conio.h>
#include <math.h>

int main()
{
float a=11,b=65,c=18,d=2;
cout<<"\texpresion original\texpresion con valores\tresultado"<<endl;
cout<<"\t(b^2)/(a^2) \t\t (65^2)/(11^2)=  \t"<<pow(b,2)/pow(a,2)<<endl;
cout<<"\n"<<endl;
cout<<"\t2(cd)^4 \t\t 2(18*2)^4= \t\t"<<2*pow(c*d,4)<<endl;
cout<<"\n"<<endl;
cout<<"\tc^2/(a+d) \t\t 18^2/(11+2)=  \t\t"<<pow(c,2)/(a+d)<<endl;
cout<<"\n"<<endl;
cout<<"\t23c/sqrt8(a+d)^2 \t(23*18)/sqrt(8(11+2)^2)=  \t"<<(23*c)/(sqrt(8.0*pow(a+d,2)))<<endl;
cout<<"\n"<<endl;
cout<<"\t15(a)/sqrt3(d)^3 \t 15(11)/sqrt(3(2)^3)=  \t"<<(15*a)/sqrt(3*pow(d,3))<<endl;

getch();
return(0);
}

problema 3:

/* practica 3 problema 3
ezequiel */
#include <iostream h>
#include <conio.h>
#include <math.h>

int main()
{
float v1=7.3,f1=110,v2=8.5,f2=90,vr1,vr2;
vr1=(120*v1)/(0.33*f1);
vr2=(110*v2)/(0.56*pow(f2,2));
cout<<"voltaje de salida del primer circuito = "<<(120*v1)/(0.33*f1)<<endl;
cout<<"\n"<<endl;
cout<<"voltaje de salida del segundo circuito = "<<(110*v2)/(0.56*pow(f2,2))<<endl;
cout<<"\n"<<endl;
cout<<"suma de los voltajes = "<<vr1+vr2<<endl;

getch();
return(0);
}

problema 4:
codigo en c++:

/* practica 3 problema 4
Ezequiel Mendez  & Walter Riedel */
#include <iostream.h>
#include <conio.h>
#include <math.h>
int main()
{
int a=0, t=0;
float poblacion=0.0;
cout<<" poblacion en miles de anios "<<endl;
for(a=2000; a<=2012; a++)
{
poblacion=6.0*(1+exp(0.2*t));
cout<<a<<"\t"<<poblacion<<endl;
t++;
}
getch();
}

problema 5:










problema 6:
codigo ec c++:

/* practica 3 problema 1
Ezequiel Mendez Gonzalez
problama 6
*/
# include <iostream.h>
# include <conio.h>
void main()
{
int r1=1000,r2=1200, r3=1500, r4=1800, total;
cout <<" caulcule la resistencia del circuito en paralelo"<<endl;
cout <<" si la ecuacion esta dada por "<<endl;
total=1.0/(1.0/r1+1.0/r2+1.0/r3+1.0/r4);
cout <<" la resistencia toral es ="<<total<<endl;
getch();
}